JEE MAIN - Physics (2023 - 8th April Evening Shift - No. 16)
Match List I with List II
LIST I | LIST II | ||
---|---|---|---|
A. | Torque | I. | $$\mathrm{ML^{-2}T^{-2}}$$ |
B. | Stress | II. | $$\mathrm{ML^2T^{-2}}$$ |
C. | Pressure gradient | III. | $$\mathrm{ML^{-1}T^{-1}}$$ |
D. | Coefficient of viscosity | IV. | $$\mathrm{ML^{-1}T^{-2}}$$ |
Choose the correct answer from the options given below:
Explanation
Let's analyze the SI units of each quantity from List I:
Torque: Torque (τ) is given by the cross product of the radius (r) and the force (F). Therefore, its SI units are Newton meter (Nm), which translates to $$\mathrm{ML^2T^{-2}}$$ in fundamental units.
Stress: Stress is force per unit area. The SI unit for force is the Newton (N) and for area is meter squared (m²). Therefore, the SI unit for stress is Pascal (Pa), which translates to $$\mathrm{ML^{-1}T^{-2}}$$ in fundamental units.
Pressure gradient: The pressure gradient is the rate of increase or decrease in pressure. It has units of pressure per distance. In SI units, that's Pascal per meter (Pa/m), which translates to $$\mathrm{ML^{-2}T^{-2}}$$ in fundamental units.
Coefficient of viscosity: This is a measure of a fluid's resistance to shear or flow, and its SI units are the Pascal second (Pa.s), which translates to $$\mathrm{ML^{-1}T^{-1}}$$ in fundamental units.
Therefore, the correct matches are:
A - II B - IV C - I D - III
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