JEE MAIN - Physics (2023 - 6th April Morning Shift - No. 17)
The energy levels of an hydrogen atom are shown below. The transition corresponding to emission of shortest wavelength is :
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A
C
B
D
Explanation
We know that, $E=\frac{h c}{\lambda}$
$$ \therefore \lambda \propto \frac{1}{E} $$
For minimum wavelength, energy must be maximum which is possible from transition $n=3$ to $n=1$.
$$ \therefore \lambda \propto \frac{1}{E} $$
For minimum wavelength, energy must be maximum which is possible from transition $n=3$ to $n=1$.
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