To calculate the centrifugal force acting on the child, we need to find the angular velocity of the merry-go-round and then apply the formula for centrifugal force.

The merry-go-round makes 1 rotation in 3.14 seconds, so its angular velocity ($$\omega$$) can be calculated as:

$$\omega = \frac{2\pi}{T}$$, where $$T$$ is the time period for one rotation.

$$\omega = \frac{2\pi}{3.14} = 2 \, \text{radians/s}$$

Now, the formula for centrifugal force ($$F$$) is:

$$F = m \cdot r \cdot \omega^2$$, where $$m$$ is the mass of the child, $$r$$ is the radius of the merry-go-round, and $$\omega$$ is the angular velocity.

$$F = 5\,\text{kg} \cdot 2\,\text{m} \cdot (2\,\text{radians/s})^2 = 5\,\text{kg} \cdot 2\,\text{m} \cdot 4\,(\text{radians/s})^2$$

$$F = 40\,\text{N}$$

Therefore, the centrifugal force on the child is $$40\,\text{N}$$.