JEE MAIN - Physics (2023 - 31st January Morning Shift - No. 9)
Two polaroide $$\mathrm{A}$$ and $$\mathrm{B}$$ are placed in such a way that the pass-axis of polaroids are perpendicular to each other. Now, another polaroid $$\mathrm{C}$$ is placed between $$\mathrm{A}$$ and $$\mathrm{B}$$ bisecting angle between them. If intensity of unpolarized light is $$\mathrm{I}_{0}$$ then intensity of transmitted light after passing through polaroid $$\mathrm{B}$$ will be:
$$\frac{I_{0}}{4}$$
$$\frac{I_{0}}{8}$$
Zero
$$\frac{I_{0}}{2}$$
Explanation
$\mathrm{I}_{\mathrm{A}}=\frac{\mathrm{I}_{\mathrm{o}}}{2}$
$\mathrm{I_C}=\frac{\mathrm{I}_{\mathrm{o}}}{2} \cos ^{2} 45=\frac{\mathrm{I}_{\mathrm{o}}}{4}$
$\mathrm{I}_{\mathrm{B}}=\mathrm{I}_{\mathrm{C}} \cos ^{2} 45=\frac{\mathrm{I}_{\mathrm{o}}}{8}$
$\mathrm{I_C}=\frac{\mathrm{I}_{\mathrm{o}}}{2} \cos ^{2} 45=\frac{\mathrm{I}_{\mathrm{o}}}{4}$
$\mathrm{I}_{\mathrm{B}}=\mathrm{I}_{\mathrm{C}} \cos ^{2} 45=\frac{\mathrm{I}_{\mathrm{o}}}{8}$
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