JEE MAIN - Physics (2023 - 31st January Morning Shift - No. 16)
The correct relation between $$\gamma = {{{c_p}} \over {{c_v}}}$$ and temperature T is :
$$\gamma \propto T$$
$$\gamma \propto {1 \over {\sqrt T }}$$
$$\gamma \propto {1 \over T}$$
$$\gamma \propto T^\circ $$
Explanation
$\gamma=\frac{C_{P}}{C_{V}}$
At low temperature $(T), \gamma$ is independent of $T$.
At low temperature $(T), \gamma$ is independent of $T$.
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