JEE MAIN - Physics (2023 - 31st January Morning Shift - No. 15)
The pressure of a gas changes linearly with volume from $$\mathrm{A}$$ to $$\mathrm{B}$$ as shown in figure. If no heat is supplied to or extracted from the gas then change in the internal energy of the gas will be
_31st_January_Morning_Shift_en_15_1.png)
6 J
4.5 J
zero
$$-$$4.5 J
Explanation
$\because \Delta Q=0$
$$ \begin{aligned} \Delta U & =-W \\\\ & =-\left[-\frac{1}{2} \times(50+10) \times 10^{3} \times 150 \times 10^{-6}\right] \\\\ & =4.5 \mathrm{~J} \end{aligned} $$
$$ \begin{aligned} \Delta U & =-W \\\\ & =-\left[-\frac{1}{2} \times(50+10) \times 10^{3} \times 150 \times 10^{-6}\right] \\\\ & =4.5 \mathrm{~J} \end{aligned} $$
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