JEE MAIN - Physics (2023 - 31st January Morning Shift - No. 14)
As shown in figure, a $$70 \mathrm{~kg}$$ garden roller is pushed with a force of $$\vec{F}=200 \mathrm{~N}$$ at an angle of $$30^{\circ}$$ with horizontal. The normal reaction on the roller is
(Given $$\mathrm{g=10~m~s^{-2}}$$)
_31st_January_Morning_Shift_en_14_1.png)
800 N
600 N
200$$\sqrt3$$ N
800$$\sqrt2$$ N
Explanation
_31st_January_Morning_Shift_en_14_2.png)
Normal reaction $=70 \mathrm{~g}+F \cos 60$
$=700+100$
$=800 \mathrm{~N}$
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