JEE MAIN - Physics (2023 - 31st January Evening Shift - No. 5)
The number of turns of the coil of a moving coil galvanometer is increased in order to increase current sensitivity by $50 \%$. The percentage change in voltage sensitivity of the galvanometer will be :
$0 \%$
$75 \%$
$100 \%$
$50 \%$
Explanation
Current sensitivity $=$ Voltage sensitivity $\times R$
Current sensitivity is made $1.5$ times.
$R$ also increase $1.5$ times.
Hence voltage sensitivity $=\frac{1.5 \times \text { current sensitivity }}{1.5 \times R}$
$$ =\text { no change } $$
Current sensitivity is made $1.5$ times.
$R$ also increase $1.5$ times.
Hence voltage sensitivity $=\frac{1.5 \times \text { current sensitivity }}{1.5 \times R}$
$$ =\text { no change } $$
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