JEE MAIN - Physics (2023 - 30th January Morning Shift - No. 7)

As per the given figure, a small ball P slides down the quadrant of a circle and hits the other ball Q of equal mass which is initially at rest. Neglecting the effect of friction and assume the collision to be elastic, the velocity of ball Q after collision will be :

(g = 10 m/s²)

JEE Main 2023 (Online) 30th January Morning Shift Physics - Center of Mass and Collision Question 23 English

0.25 m/s

4 m/s

2 m/s

Explanation

JEE Main 2023 (Online) 30th January Morning Shift Physics - Center of Mass and Collision Question 23 English Explanation

Mass is same and elastic collision, so speed gets exchanged, $$v=2$$ m/s

JEE MAIN - Physics (2023 - 30th January Morning Shift - No. 7)

Explanation

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