JEE MAIN - Physics (2023 - 30th January Morning Shift - No. 4)
Choose the correct relationship between Poisson ratio $$(\sigma)$$, bulk modulus (K) and modulus of rigidity $$(\eta)$$ of a given solid object :
$$\sigma=\frac{3 K+2 \eta}{6 K+2 \eta}$$
$$\sigma=\frac{3 K-2 \eta}{6 K+2 \eta}$$
$$\sigma=\frac{6 K+2 \eta}{3 K-2 \eta}$$
$$\sigma=\frac{6 K-2 \eta}{3 K-2 \eta}$$
Explanation
Poisson ratio ($$\sigma$$), bulk modulus (K) and modulus of rigidity ($$\eta$$) are related by
$$\because 2\eta(1+\sigma)=3K(1-2\sigma)$$
$$2\eta+2\eta\sigma=3K-6K\sigma$$
$$\sigma=\frac{3K-2\eta}{2\eta+6K}$$
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