JEE MAIN - Physics (2023 - 30th January Morning Shift - No. 26)
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As per the given figure, if $$\frac{\mathrm{dI}}{\mathrm{dt}}=-1 \mathrm{~A} / s$$ then the value of $$\mathrm{V}_{\mathrm{AB}}$$ at this instant will be ____________ $$\mathrm{V}$$.
Answer
30
Explanation
From the circuit :
$${V_A} - iR - {{Ldi} \over {dt}} - 12 = {V_B}$$
$$ \Rightarrow {V_A} - {V_B} = 2 \times 12 + 6( - 1) + 12$$ volts
$$ = 30$$ volts
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