JEE MAIN - Physics (2023 - 30th January Morning Shift - No. 16)
Match Column-I with Column-II :
| Column-I ($$x$$-t graphs) |
Column-II ($$v$$-t graphs) |
||
|---|---|---|---|
| A. | _30th_January_Morning_Shift_en_16_1.png) |
I. | _30th_January_Morning_Shift_en_16_2.png) |
| B. | _30th_January_Morning_Shift_en_16_3.png) |
II. | _30th_January_Morning_Shift_en_16_4.png) |
| C. | _30th_January_Morning_Shift_en_16_5.png) |
III. | _30th_January_Morning_Shift_en_16_6.png) |
| D. | _30th_January_Morning_Shift_en_16_7.png) |
IV. | _30th_January_Morning_Shift_en_16_8.png) |
Choose the correct answer from the options given below:
A- II, B-III, C-IV, D-I
A- II, B-IV, C-III, D-I
A- I, B-III, C-IV, D-II
A- I, B-II, C-III, D-IV
Explanation
$$
\begin{aligned}
& \frac{\mathrm{dx}}{\mathrm{dt}}=\text { slope } \geq 0 \text { always increasing } \\\\
& (\mathrm{A} \text { - II) } \\\\
& \frac{\mathrm{dx}}{\mathrm{dt}}<0 \text {; and at } \mathrm{t} \rightarrow \infty \frac{\mathrm{dx}}{\mathrm{dt}} \rightarrow 0 \\\\
& \text { (B - IV) } \\\\
& \frac{\mathrm{dx}}{\mathrm{dt}}>0 \text { for first half } \frac{\mathrm{dx}}{\mathrm{dt}}<0 \text { for second half. } \\\\
& (\mathrm{C} \text { - III) } \\\\
& \frac{\mathrm{dx}}{\mathrm{dt}}=\text { constant } \\\\
& \text { (D - I) }
\end{aligned}
$$
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