JEE MAIN - Physics (2023 - 30th January Evening Shift - No. 13)

A flask contains hydrogen and oxygen in the ratio of $2: 1$ by mass at temperature $27^{\circ} \mathrm{C}$. The ratio of average kinetic energy per molecule of hydrogen and oxygen respectively is:

1 : 1

4 : 1

1 : 4

2 : 1

Explanation

K.E. per molecule $$ = \left( {{f \over 2}KT} \right)$$

$${{\mathrm{average{{(K.E)}_{hydrogen}}}} \over {\mathrm{average{{(K.E)}_{oxygen}}}}} = {{{f_{\mathrm{hydrogen}}}} \over {{f_{\mathrm{oxygen}}}}} = 1$$

JEE MAIN - Physics (2023 - 30th January Evening Shift - No. 13)

Explanation

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