JEE MAIN - Physics (2023 - 30th January Evening Shift - No. 11)
A block of $\sqrt{3} \mathrm{~kg}$ is attached to a string whose other end is attached to the wall. An unknown force $\mathrm{F}$ is applied so that the string makes an angle of $30^{\circ}$ with the wall. The tension $\mathrm{T}$ is:
(Given $\mathrm{g}=10 \mathrm{~ms}^{-2}$ )
_30th_January_Evening_Shift_en_11_1.png)
15 N
10 N
25 N
20 N
Explanation
Drawing the FBD of the point where $$F$$ is applied
_30th_January_Evening_Shift_en_11_2.png)
$$T' = \sqrt 3 g$$
$$ \Rightarrow T\cos 30^\circ = \sqrt 3 g$$
$$ \Rightarrow T = 2g = 20$$ N
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