JEE MAIN - Physics (2023 - 29th January Morning Shift - No. 3)
In a cuboid of dimension $$2 \mathrm{~L} \times 2 \mathrm{~L} \times \mathrm{L}$$, a charge $$q$$ is placed at the center of the surface '$$\mathrm{S}$$' having area of $$4 \mathrm{~L}^{2}$$. The flux through the opposite surface to '$$\mathrm{S}$$' is given by
$$\frac{q}{2 \epsilon_{0}}$$
$$\frac{q}{3 \epsilon_{0}}$$
$$\frac{q}{12 \epsilon_{0}}$$
$$\frac{q}{6 \in_{0}}$$
Explanation
_29th_January_Morning_Shift_en_3_1.png)
If we consider a similar box above this box then it becomes cube of side length $2 L$
$\phi$ through a surface $=\frac{q}{6 \varepsilon_{0}}$
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