JEE MAIN - Physics (2023 - 29th January Evening Shift - No. 24)
Unpolarised light is incident on the boundary between two dielectric media, whose dielectric constants are 2.8 (medium $$-1$$) and 6.8 (medium $$-2$$), respectively. To satisfy the condition, so that the reflected and refracted rays are perpendicular to each other, the angle of incidence should be $${\tan ^{ - 1}}{\left( {1 + {{10} \over \theta }} \right)^{{1 \over 2}}}$$ the value of $$\theta$$ is __________.
(Given for dielectric media, $$\mu_r=1$$)
Answer
7
Explanation
We know that
$$\tan {\theta _0} = {{{\mu _2}} \over {{\mu _1}}}$$
$$\tan {\theta _0} = \sqrt {{{6.8} \over {2.8}}} = \sqrt {{{17} \over 7}} $$
$${\theta _0} = {\tan ^{ - 1}}\sqrt {1 + {{10} \over 7}} \Rightarrow \theta = 7$$
Comments (0)
