JEE MAIN - Physics (2023 - 25th January Morning Shift - No. 9)
A car travels a distance of '$$x$$' with speed $$v_1$$ and then same distance '$$x$$' with speed $$v_2$$ in the same direction. The average speed of the car is :
$${{{v_1}{v_2}} \over {2({v_1} + {v_2})}}$$
$${{2{v_1}{v_2}} \over {{v_1} + {v_2}}}$$
$${{2x} \over {{v_1} + {v_2}}}$$
$${{{v_1} + {v_2}} \over 2}$$
Explanation
$$
\begin{aligned}
& \text { Average velocity }=\frac{\text { Total displacement }}{\text { Total time }} \\\\
& =\frac{\mathrm{x}+\mathrm{x}}{\frac{\mathrm{x}}{\mathrm{v}_1}+\frac{\mathrm{x}}{\mathrm{v}_2}}=\frac{2 \mathrm{v}_1 \mathrm{v}_2}{\mathrm{v}_1+\mathrm{v}_2}
\end{aligned}
$$
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