JEE MAIN - Physics (2023 - 25th January Morning Shift - No. 22)
The distance between two consecutive points with phase difference of 60$$^\circ$$ in a wave of frequency 500 Hz is 6.0 m. The velocity with which wave is travelling is __________ km/s
Answer
18
Explanation
$$ \begin{aligned} & \Delta x=\frac{\lambda}{2 \pi} \times\left(\frac{\pi}{3}\right)=\left(\frac{\lambda}{6}\right) \\\\ & \Rightarrow \quad \frac{\lambda}{6}=6 \mathrm{~m} \\\\ & \quad \lambda=36 \mathrm{~m} \\\\ & U=f\lambda=500 \mathrm{~Hz} \times 36 \\\\ & =18000 \mathrm{~m} / \mathrm{s} \\\\ & =18 \mathrm{~km} / \mathrm{s} \end{aligned} $$
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