JEE MAIN - Physics (2023 - 25th January Evening Shift - No. 5)
A wire of length 1m moving with velocity 8 m/s at right angles to a magnetic field of 2T. The magnitude of induced emf, between the ends of wire will be __________.
20 V
8 V
16 V
12 V
Explanation
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Induced emf across the ends = Bv$l$
= 2 × 8 × 1 = 16 V
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