JEE MAIN - Physics (2023 - 25th January Evening Shift - No. 16)
A body of mass is taken from earth surface to the height h equal to twice the radius of earth (R$$_e$$), the increase in potential energy will be :
(g = acceleration due to gravity on the surface of Earth)
$$\frac{1}{2}mgR_e$$
$$3~mgR_e$$
$$\frac{1}{3}mgR_e$$
$$\frac{2}{3}mgR_e$$
Explanation
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