JEE MAIN - Physics (2023 - 25th January Evening Shift - No. 15)
According to law of equipartition of energy the molar specific heat of a diatomic gas at constant volume where the molecule has one additional vibrational mode is :-
$$\frac{9}{2}R$$
$$\frac{5}{2}R$$
$$\frac{3}{2}R$$
$$\frac{7}{2}R$$
Explanation
Diatomic gas molecules have three translational degree of freedom, two rotational degree of freedom \& it is given that it has one vibrational mode so there are two additional degree of freedom corresponding to one vibrational mode, so total degree of freedom $=7$
$$ \mathrm{C}_{\mathrm{v}}=\frac{\mathrm{fR}}{2}=\frac{7 \mathrm{R}}{2} $$
$$ \mathrm{C}_{\mathrm{v}}=\frac{\mathrm{fR}}{2}=\frac{7 \mathrm{R}}{2} $$
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