JEE MAIN - Physics (2023 - 25th January Evening Shift - No. 10)
The graph between two temperature scales P and Q is shown in the figure. Between upper fixed point and lower fixed point there are 150 equal divisions of scale P and 100 divisions on scale Q. The relationship for conversion between the two scales is given by :-
_25th_January_Evening_Shift_en_10_1.png)
$${{{t_P}} \over {100}} = {{{t_Q} - 180} \over {150}}$$
$${{{t_P}} \over {180}} - {{{t_Q} - 40} \over {100}}$$
$${{{t_Q}} \over {150}} = {{{t_P} - 180} \over {100}}$$
$${{{t_Q}} \over {100}} = {{{t_P} - 30} \over {150}}$$
Explanation
$$
\begin{aligned}
& \frac{\text { reading on scale }-\text { Lower fixed point }}{\text { upper fixed point-lower fixed point }}=\text { constant } \\\\
& \frac{t_P-30}{180-30}=\frac{t_Q-0}{100-0} \\\\
& \frac{t_P-30}{150}=\frac{t_Q}{100}
\end{aligned}
$$
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