JEE MAIN - Physics (2023 - 24th January Morning Shift - No. 22)
A hole is drilled in a metal sheet. At $$\mathrm{27^\circ
C}$$, the diameter of hole is 5 cm. When the sheet is heated to $$\mathrm{177^\circ
C}$$, the change in the diameter of hole is $$\mathrm{d\times10^{-3}}$$ cm. The value of d will be __________ if coefficient of linear expansion of the metal is $$1.6\times10^{-5}/^\circ$$C.
Answer
12
Explanation
$\Delta D=D \alpha \Delta t$
$$ \begin{aligned} & =5 \times 1.6 \times 10^{-5}(177-27) \\\\ & =0.012 \mathrm{~cm} \\\\ & =12 \times 10^{-3} \mathrm{~cm} \\\\ & \text { so, } d=12 \end{aligned} $$
$$ \begin{aligned} & =5 \times 1.6 \times 10^{-5}(177-27) \\\\ & =0.012 \mathrm{~cm} \\\\ & =12 \times 10^{-3} \mathrm{~cm} \\\\ & \text { so, } d=12 \end{aligned} $$
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