JEE MAIN - Physics (2023 - 24th January Morning Shift - No. 16)
Match List I with List II
| List-I |
List-II |
||
|---|---|---|---|
| A. | Planck's constant (h) | I. | $$\mathrm{[{M^1}\,{L^2}\,{T^{ - 2}}]}$$ |
| B. | Stopping potential (Vs) | II. | $$\mathrm{[{M^1}\,{L^1}\,{T^{ - 1}}]}$$ |
| C. | Work function ($$\phi$$) | III. | $$\mathrm{[{M^1}\,{L^2}\,{T^{ - 1}}]}$$ |
| D. | Momentum (p) | IV. | $$\mathrm{[{M^1}\,{L^2}\,{T^{ - 3}}\,{A^{ - 1}}]}$$ |
Choose the correct answer from the options given below :
A-I, B-III, C-IV, D-II
A-III, B-IV, C-I, D-II
A-II, B-IV, C-III, D-I
A-III, B-I, C-II, D-IV
Explanation
(A) Planck's constant
$$ \begin{aligned} & \mathrm{h} v=\mathrm{E} \\\\ & \mathrm{h}=\frac{\mathrm{E}}{v}=\frac{\mathrm{M}^1 \mathrm{~L}^2 \mathrm{~T}^{-2}}{\mathrm{~T}^{-1}}=\mathrm{M}^1 \mathrm{~L}^2 \mathrm{~T}^{-1} \quad...(\text{III}) \end{aligned} $$
(B) $\mathrm{E}=\mathrm{qV}$
$$ V=\frac{E}{q}=\frac{M^1 L^2 T^{-2}}{A^1 T^1}=M^1 L^2 T^{-3} A^{-1} \text { (IV) } $$
(C) $\phi($ work function $)=$ energy
$$ =\mathrm{M}^1 \mathrm{~L}^2 \mathrm{~T}^{-2} \quad....(\text{I}) $$
(D) Momentum (p) = F.t
$$ \begin{aligned} & =\mathrm{M}^1 \mathrm{~L}^1 \mathrm{~T}^{-2} \mathrm{~T}^1 \\\\ & =\mathrm{M}^1 \mathrm{~L}^1 \mathrm{~T}^{-1} \quad....(\text{II}) \end{aligned} $$
$$ \begin{aligned} & \mathrm{h} v=\mathrm{E} \\\\ & \mathrm{h}=\frac{\mathrm{E}}{v}=\frac{\mathrm{M}^1 \mathrm{~L}^2 \mathrm{~T}^{-2}}{\mathrm{~T}^{-1}}=\mathrm{M}^1 \mathrm{~L}^2 \mathrm{~T}^{-1} \quad...(\text{III}) \end{aligned} $$
(B) $\mathrm{E}=\mathrm{qV}$
$$ V=\frac{E}{q}=\frac{M^1 L^2 T^{-2}}{A^1 T^1}=M^1 L^2 T^{-3} A^{-1} \text { (IV) } $$
(C) $\phi($ work function $)=$ energy
$$ =\mathrm{M}^1 \mathrm{~L}^2 \mathrm{~T}^{-2} \quad....(\text{I}) $$
(D) Momentum (p) = F.t
$$ \begin{aligned} & =\mathrm{M}^1 \mathrm{~L}^1 \mathrm{~T}^{-2} \mathrm{~T}^1 \\\\ & =\mathrm{M}^1 \mathrm{~L}^1 \mathrm{~T}^{-1} \quad....(\text{II}) \end{aligned} $$
Comments (0)
