JEE MAIN - Physics (2023 - 24th January Morning Shift - No. 13)
A travelling wave is described by the equation
$$y(x,t) = [0.05\sin (8x - 4t)]$$ m
The velocity of the wave is : [all the quantities are in SI unit]
$$\mathrm{4~ms^{-1}}$$
$$\mathrm{2~ms^{-1}}$$
$$\mathrm{8~ms^{-1}}$$
$$\mathrm{0.5~ms^{-1}}$$
Explanation
$\because y(x, t)=[0.05 \sin (8 x-4 t)] \mathrm{m}$
$$ \begin{aligned} \text { Speed of wave } & =\left|\frac{\text { Coefficient of } t}{\text { Coefficient of } x}\right| \\\\ & =\frac{4}{8}=0.5 \mathrm{~ms}^{-1} \end{aligned} $$
$$ \begin{aligned} \text { Speed of wave } & =\left|\frac{\text { Coefficient of } t}{\text { Coefficient of } x}\right| \\\\ & =\frac{4}{8}=0.5 \mathrm{~ms}^{-1} \end{aligned} $$
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