JEE MAIN - Physics (2023 - 24th January Evening Shift - No. 29)
Three identical resistors with resistance R = 12$$\Omega$$ and two identical inductors with self inductance L = 5 mH are connected to an ideal battery with emf of 12 V as shown in figure. The current through the battery long after the switch has been closed will be _____________ A.
_24th_January_Evening_Shift_en_29_1.png)
Answer
3
Explanation
After long time, inductors are shorted.
Effective circuit becomes
_24th_January_Evening_Shift_en_29_2.png)
Current through battery $=\frac{V}{\mathrm{R}_{\mathrm{eq}}}=\frac{12 \mathrm{~V}}{4 \Omega}=3 \mathrm{~A}$
where $\mathrm{R}_{\mathrm{eq}}=3$ resistors in parallel.
Comments (0)
