JEE MAIN - Physics (2023 - 15th April Morning Shift - No. 25)
A network of four resistances is connected to $9 \mathrm{~V}$ battery, as shown in figure. The magnitude of voltage difference between the points $\mathrm{A}$ and $\mathrm{B}$ is __________ $V$.
_15th_April_Morning_Shift_en_25_1.png)
Answer
3
Explanation
_15th_April_Morning_Shift_en_25_2.png)
In the circuit $I=\frac{9}{3}=3 \mathrm{~A}$
$$ \mathrm{V}_{\mathrm{C}}-\mathrm{V}_{\mathrm{A}}=2 \times 1.5=3~~......(I) $$
$$ \mathrm{V}_{\mathrm{C}}-\mathrm{V}_{\mathrm{B}}=4 \times 1.5=6~~......(II) $$
$\mathrm{Eq}^{\mathrm{n}}(\mathrm{II})-\mathrm{Eq}^{\mathrm{n}}(\mathrm{I})$
$$ \mathrm{V}_{\mathrm{A}}-\mathrm{V}_{\mathrm{B}}=6-3=3 \text { Volt } $$
Comments (0)
