JEE MAIN - Physics (2023 - 15th April Morning Shift - No. 16)

Match List I with List II of Electromagnetic waves with corresponding wavelength range :

List I List II
(A) Microwave (I) $400 \mathrm{~nm}$ to $1 \mathrm{~nm}$
(B) Ultraviolet (II) $1 \mathrm{~nm}$ to $10^{-3} \mathrm{~nm}$
(C) X-Ray (III) $1 \mathrm{~mm}$ to $700 \mathrm{~nm}$
(D) Infra-red (IV) $0.1 \mathrm{~m}$ to $1 \mathrm{~mm}$

Choose the correct answer from the options given below:
(A)-(I), (B)-(IV), (C)-(II), (D)-(III)
(A)-(IV), (B)-(I), (C)-(II), (D)-(III)
(A)-(IV), (B)-(I), (C)-(III), (D) -(II)
(A)-(IV), (B)-(II), (C)-(I), (D)-(III)

Explanation

The correct matching of the electromagnetic waves with their corresponding wavelength ranges is:

(A) Microwave --> (IV) 0.1 m to 1 mm

(B) Ultraviolet --> (I) 400 nm to 1 nm

(C) X-Ray --> (II) 1 nm to $10^{-3}$ nm

(D) Infra-red --> (III) 1 mm to 700 nm

Therefore, the correct option is (A-IV, B-I, C-II, D-III).

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