JEE MAIN - Physics (2023 - 15th April Morning Shift - No. 14)
A thermodynamic system is taken through cyclic process. The total work done in the process is :
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$100 \mathrm{~J}$
Zero
$300 \mathrm{~J}$
$200 \mathrm{~J}$
Explanation
On $\mathrm{P}-\mathrm{V}$ scale area of loop $=$ work done
$$ \begin{aligned} & \Rightarrow \mathrm{W}=+\frac{1}{2}(2) \times 300 \\\\ & \mathrm{~W}=300 \mathrm{~J} \end{aligned} $$
$$ \begin{aligned} & \Rightarrow \mathrm{W}=+\frac{1}{2}(2) \times 300 \\\\ & \mathrm{~W}=300 \mathrm{~J} \end{aligned} $$
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