JEE MAIN - Physics (2023 - 13th April Evening Shift - No. 8)
In an electromagnetic wave, at an instant and at particular position, the electric field is along the negative $$z$$-axis and magnetic field is along the positive $$x$$-axis. Then the direction of propagation of electromagnetic wave is:
at $$45^{\circ}$$ angle from positive y-axis
positive $$y$$-axis
negative $$\mathrm{y}$$-axis
positive z-axis
Explanation
As the electric field is along the negative $z$-axis and the magnetic field is along the positive $x$-axis, the direction of propagation of the wave is given by the vector product $\overrightarrow{\mathrm{E}} \times \overrightarrow{\mathrm{B}}$, which is in the direction of the negative $y$-axis.
Using the right-hand rule, if you point your right thumb in the direction of the vector product $\overrightarrow{\mathrm{E}} \times \overrightarrow{\mathrm{B}}$, your fingers will curl in the direction of the propagation of the wave. In this case, the fingers would curl in the direction of the negative $y$-axis.
Therefore, the direction of propagation of the electromagnetic wave in this scenario is along the negative $y$-axis.
Using the right-hand rule, if you point your right thumb in the direction of the vector product $\overrightarrow{\mathrm{E}} \times \overrightarrow{\mathrm{B}}$, your fingers will curl in the direction of the propagation of the wave. In this case, the fingers would curl in the direction of the negative $y$-axis.
Therefore, the direction of propagation of the electromagnetic wave in this scenario is along the negative $y$-axis.
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