JEE MAIN - Physics (2023 - 13th April Evening Shift - No. 6)
A vehicle of mass $$200 \mathrm{~kg}$$ is moving along a levelled curved road of radius $$70 \mathrm{~m}$$ with angular velocity of $$0.2 ~\mathrm{rad} / \mathrm{s}$$. The centripetal force acting on the vehicle is:
$$560 \mathrm{~N}$$
$$14 \mathrm{~N}$$
$$2800 \mathrm{~N}$$
$$2240 \mathrm{~N}$$
Explanation
The centripetal force acting on an object moving along a circular path of radius $$r$$ and angular velocity $$\omega$$ is given by:
$$F_c=mr\omega^2$$
where $$m$$ is the mass of the object.
In this problem, the vehicle of mass $$m=200 \mathrm{~kg}$$ is moving along a circular path of radius $$r=70 \mathrm{~m}$$ with angular velocity $$\omega=0.2 ~\mathrm{rad}/\mathrm{s}$$.
Substituting the given values into the formula, we get:
$$F_c=mr\omega^2=(200~\mathrm{kg})(70~\mathrm{m})(0.2~\mathrm{rad/s})^2=\boxed{560~\mathrm{N}}$$
Therefore, the centripetal force acting on the vehicle is $$560~\mathrm{N}$$.
$$F_c=mr\omega^2$$
where $$m$$ is the mass of the object.
In this problem, the vehicle of mass $$m=200 \mathrm{~kg}$$ is moving along a circular path of radius $$r=70 \mathrm{~m}$$ with angular velocity $$\omega=0.2 ~\mathrm{rad}/\mathrm{s}$$.
Substituting the given values into the formula, we get:
$$F_c=mr\omega^2=(200~\mathrm{kg})(70~\mathrm{m})(0.2~\mathrm{rad/s})^2=\boxed{560~\mathrm{N}}$$
Therefore, the centripetal force acting on the vehicle is $$560~\mathrm{N}$$.
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