JEE MAIN - Physics (2023 - 11th April Morning Shift - No. 12)
Explanation
To find the number of bullets fired per second, we can use the concept of momentum. When the machine gun fires bullets, it experiences a backward force due to the conservation of momentum. The force applied on the machine gun is used to balance this backward force.
First, let's find the momentum of each bullet:
Momentum = Mass × Velocity
Bullet mass = $$10 \mathrm{~g} = 0.01 \mathrm{~kg}$$ Bullet velocity = $$250 \mathrm{~m/s}$$
Momentum per bullet = $$0.01 \mathrm{~kg} \cdot 250 \mathrm{~m/s} = 2.5 \mathrm{~kg \cdot m/s}$$
Now let's find the momentum per second that needs to be balanced by the applied force:
Force = $$125 \mathrm{~N}$$
Momentum per second = Force × Time
Since we are considering a time interval of 1 second, the momentum per second is equal to the applied force:
Momentum per second = $$125 \mathrm{~N}$$
Now, let's find the number of bullets fired per second:
Number of bullets = Momentum per second / Momentum per bullet
Number of bullets = $$\frac{125 \mathrm{~N}}{2.5 \mathrm{~kg \cdot m/s}}$$
Number of bullets = 50
Therefore, the machine gun fires 50 bullets per second.
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