JEE MAIN - Physics (2023 - 11th April Evening Shift - No. 26)
In the given circuit, $$\mathrm{C}_{1}=2 \mu \mathrm{F}, \mathrm{C}_{2}=0.2 \mu \mathrm{F}, \mathrm{C}_{3}=2 \mu \mathrm{F}, \mathrm{C}_{4}=4 \mu \mathrm{F}, \mathrm{C}_{5}=2 \mu \mathrm{F}, \mathrm{C}_{6}=2 \mu \mathrm{F}$$, The charge stored on capacitor $$\mathrm{C}_{4}$$ is ____________ $$\mu \mathrm{C}$$.
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Answer
4
Explanation
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$$ \begin{aligned} & \mathrm{C}_{\mathrm{eq}}=0.5 \mu \mathrm{F} \\\\ & \mathrm{Q}=0.5 \times 10=5 \mu \mathrm{C} \\\\ & \mathrm{Q}^{\prime}=\frac{5 \mu \mathrm{C} \times 0.8}{0.8+0.2}=4 \mu \mathrm{C} \end{aligned} $$
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