JEE MAIN - Physics (2023 - 11th April Evening Shift - No. 19)
As shown in the figure, a plane mirror is fixed at a height of $$50 \mathrm{~cm}$$ from the bottom of tank containing water $$\left(\mu=\frac{4}{3}\right)$$. The height of water in the tank is $$8 \mathrm{~cm}$$. A small bulb is placed at the bottom of the water tank. The distance of image of the bulb formed by mirror from the bottom of the tank is ___________ $$\mathrm{cm}$$.
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Answer
98
Explanation
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$$ \text { Apparent depth of } \mathrm{O}=\frac{\mathrm{d}}{\mu} $$$$ =\frac{8}{\frac{4}{3}}=6 \mathrm{~cm} $$
Distance of object from mirror = 42 + 6 = 48 m
$$ \text { Distance between } \mathrm{O} \text { and } \mathrm{I}_2=48+50=98 \mathrm{~cm} $$
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