JEE MAIN - Physics (2022 - 30th June Morning Shift - No. 8)
The pressure of the gas in a constant volume gas thermometer is 100 cm of mercury when placed in melting ice at 1 atm. When the bulb is placed in a liquid, the pressure becomes 180 cm of mercury. Temperature of the liquid is :
(Given 0$$^\circ$$C = 273 K)
300 K
400 K
600 K
491 K
Explanation
Here volume is constant.
$$\therefore$$ $${{{P_1}} \over {{T_1}}} = {{{P_2}} \over {{T_2}}}$$
$$ \Rightarrow {{100} \over {273}} = {{180} \over {{T_2}}}$$
$$ \Rightarrow {T_2} = {{180} \over {100}} \times 273$$
$$ = 1.8 \times 273$$
$$ = 491\,K$$
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