JEE MAIN - Physics (2022 - 29th June Morning Shift - No. 8)
A charge particle moves along circular path in a uniform magnetic field in a cyclotron. The kinetic energy of the charge particle increases to 4 times its initial value. What will be the ratio of new radius to the original radius of circular path of the charge particle :
1 : 1
1 : 2
2 : 1
1 : 4
Explanation
$$R = {{mv} \over {Bq}} = {{\sqrt {2mK} } \over {Bq}}$$
$$ \Rightarrow R \propto \sqrt K $$
$$\Rightarrow$$ ratio = 2 : 1
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