JEE MAIN - Physics (2022 - 29th June Morning Shift - No. 3)
A spherical shell of 1 kg mass and radius R is rolling with angular speed $$\omega$$ on horizontal plane (as shown in figure). The magnitude of angular momentum of the shell about the origin O is $${a \over 3}$$ R2$$\omega$$. The value of a will be :
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2
3
5
4
Explanation
$${\overrightarrow L _0} = {\overrightarrow L _{of\,cm}} + {\overrightarrow L _{about\,cm}}$$
$$ \Rightarrow {a \over 3}{R^2}\omega = mvR + {2 \over 3}m{R^2}\omega = {5 \over 3}m{R^2}\omega $$
$$ \Rightarrow a = 5$$
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