JEE MAIN - Physics (2022 - 29th June Morning Shift - No. 23)
$$\sqrt {{d_1}} $$ and $$\sqrt {{d_2}} $$ are the impact parameters corresponding to scattering angles 60$$^\circ$$ and 90$$^\circ$$ respectively, when an $$\alpha$$ particle is approaching a gold nucleus. For d1 = x d2, the value of x will be ____________.
Answer
3
Explanation
Impact parameter $$\propto$$ $$\cot {\theta \over 2}$$
$$ \Rightarrow \sqrt {{{{d_1}} \over {{d_2}}}} = {{\sqrt 3 } \over 1}$$
$$ \Rightarrow {d_1} = 3{d_2}$$
$$ \Rightarrow x = 3$$
Comments (0)
