JEE MAIN - Physics (2022 - 29th June Morning Shift - No. 15)
A parallel plate capacitor filled with a medium of dielectric constant 10, is connected across a battery and is charged. The dielectric slab is replaced by another slab of dielectric constant 15. Then the energy of capacitor will :
increase by 50%
decrease by 15%
increase by 25%
increase by 33%
Explanation
$$U = {1 \over 2}(k{C_0}){V^2}$$
$$ \Rightarrow {{U'} \over U} = 1.5$$
$$\Rightarrow$$ Energy increases by 50%
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