JEE MAIN - Physics (2022 - 29th June Evening Shift - No. 9)
The time period of a satellite revolving around earth in a given orbit is 7 hours. If the radius of orbit is increased to three times its previous value, then approximate new time period of the satellite will be
40 hours
36 hours
30 hours
25 hours
Explanation
$$T_2^2 = {\left( {{{{R_2}} \over {{R_1}}}} \right)^3}T_1^2$$
$$ \Rightarrow {T_2} = {(3)^{3/2}} \times 7 \approx 5.2 \times 7$$
$${T_2} \cong 36$$ hrs
Comments (0)
