JEE MAIN - Physics (2022 - 29th June Evening Shift - No. 2)
At what temperature a gold ring of diameter 6.230 cm be heated so that it can be fitted on a wooden bangle of diameter 6.241 cm ? Both the diameters have been measured at room temperature (27$$^\circ$$C).
(Given : coefficient of linear thermal expansion of gold $$\alpha$$L = 1.4 $$\times$$ 10$$-$$5 K$$-$$1)
125.7$$^\circ$$C
91.7$$^\circ$$C
425.7$$^\circ$$C
152.7$$^\circ$$C
Explanation
$$\Delta D = D\alpha \Delta T$$
$$\Delta T = {{0.011} \over {6.230 \times 1.4 \times {{10}^{ - 5}}}}$$
= 126.11$$^\circ$$C
$$\Rightarrow$$ Tf = T + $$\Delta$$T
= (27 + 126.11)$$^\circ$$C
= 153.11$$^\circ$$C
Comments (0)
