JEE MAIN - Physics (2022 - 29th June Evening Shift - No. 14)

In the given figure, the block of mass m is dropped from the point 'A'. The expression for kinetic energy of block when it reaches point 'B' is

JEE Main 2022 (Online) 29th June Evening Shift Physics - Work Power & Energy Question 66 English

$${1 \over 2}mg\,{y_0}^2$$
$${1 \over 2}mg\,{y^2}$$
$$mg(y - {y_0})$$
$$mg{y_0}$$

Explanation

Loss in potential energy = gain in kinetic energy

$$-$$ (mg(y $$-$$ y0) $$-$$ mgy) = KE $$-$$ 0

$$\Rightarrow$$ KE = mgy0

Comments (0)

Advertisement