JEE MAIN - Physics (2022 - 29th June Evening Shift - No. 13)
A block of mass 40 kg slides over a surface, when a mass of 4 kg is suspended through an inextensible massless string passing over frictionless pulley as shown below.
The coefficient of kinetic friction between the surface and block is 0.02. The acceleration of block is. (Given g = 10 ms$$-$$2.)
_29th_June_Evening_Shift_en_13_1.png)
1 ms$$-$$2
1/5 ms$$-$$2
4/5 ms$$-$$2
8/11 ms$$-$$2
Explanation
_29th_June_Evening_Shift_en_13_2.png)
$${f_{{r_{\max }}}} = \mu N$$
$$ = 0.02 \times 400$$
= 8 N
Let the acceleration is a as shown then.
$$40 - T = 4a$$
$$T - 8 = 40a$$
$$ \Rightarrow a = {{32} \over {44}} = {8 \over {11}}$$ m/s2
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