JEE MAIN - Physics (2022 - 29th July Morning Shift - No. 29)
If the potential barrier across a p-n junction is $$0.6 \mathrm{~V}$$. Then the electric field intensity, in the depletion region having the width of $$6 \times 10^{-6} \mathrm{~m}$$, will be __________ $$\times 10^{5} \mathrm{~N} / \mathrm{C}$$.
Answer
1
Explanation
$$E = {V \over d} = {{0.6} \over {6 \times {{10}^{ - 6}}}} = 1 \times {10^5}$$
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