JEE MAIN - Physics (2022 - 29th July Morning Shift - No. 27)
A wire of length $$314 \mathrm{~cm}$$ carrying current of $$14 \mathrm{~A}$$ is bent to form a circle. The magnetic moment of the coil is ________ A $$-\mathrm{m}^{2}$$. [Given $$\pi=3.14$$]
Answer
11
Explanation
$$R = {l \over {2\pi }} = {{314} \over {2 \times 3.14}} = 50$$ cm
$$\mu = \pi {R^2}i$$
$$ = 14 \times 3.14 \times {(0.5)^2}$$
$$ = 11$$ A-m2
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