JEE MAIN - Physics (2022 - 29th July Morning Shift - No. 26)
Two light beams of intensities 4I and 9I interfere on a screen. The phase difference between these beams on the screen at point A is zero and at point B is $$\pi$$. The difference of resultant intensities, at the point A and B, will be _________ I.
Answer
24
Explanation
$${I_A} = {\left( {\sqrt {{I_1}} + \sqrt {{I_2}} } \right)^2} = 25I$$
$${I_B} = {\left( {\sqrt {{I_1}} - \sqrt {{I_2}} } \right)^2} = I$$
So, $${I_A} - {I_B} = 24I$$
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