At steady state charge stored on the capacitor,

$${q_{\max }} = CV$$

$$ = 500 \times {10^{ - 6}} \times 100$$

$$ = 5 \times {10^{ - 2}}\,C$$

Energy stored in the capacitor,

$${U_{\max }} = {{q_{\max }^2} \over {2C}}$$

Now, when electrostatic energy of capacitor converted to magnetic field energy then all energy of capacitor is transferrd to the inductor.

$$\therefore$$ Maximum energy stored in the inductor

$${U_{L\,\max }} = {1 \over 2}L\,I_{\max }^2$$

$$\therefore$$ $${1 \over 2}L\,I_{\max }^2 = {{q_{\max }^2} \over {2C}}$$

$$ \Rightarrow {I_{\max }} = {{{q_{\max }}} \over {\sqrt {LC} }}$$

$$ = {{5 \times {{10}^{ - 2}}} \over {\sqrt {50 \times {{10}^{ - 3}} \times 500 \times {{10}^{ - 6}}} }}$$

$$ = {{5 \times {{10}^{ - 2}}} \over {5 \times {{10}^{ - 3}}}}$$

$$ = 10\,A$$