JEE MAIN - Physics (2022 - 29th July Evening Shift - No. 25)
A $$8 \mathrm{~V}$$ Zener diode along with a series resistance $$\mathrm{R}$$ is connected across a $$20 \mathrm{~V}$$ supply (as shown in the figure). If the maximum Zener current is $$25 \mathrm{~mA}$$, then the minimum value of R will be _______ $$\Omega$$.
_29th_July_Evening_Shift_en_25_1.png)
Answer
480
Explanation
_29th_July_Evening_Shift_en_25_2.png)
Applying voltage rule in loop ABCD.
$$ \begin{aligned} \mathrm{E}-\mathrm{IR}-\mathrm{V}_{\mathrm{Z}} & =0 \\\\ 20-\mathrm{IR}-8 & =0 \\\\ 2.5 \times 10^{-3} \times \mathrm{R} & =12 \end{aligned} $$
$\mathrm{R}=\frac{12}{25 \times 10^{-3}}=480 \Omega$
Comments (0)
