JEE MAIN - Physics (2022 - 28th June Morning Shift - No. 4)
Match List-I with List-II
| List-I | List-II | ||
|---|---|---|---|
| (A) | Moment of inertia of solid sphere of radius R about any tangent. | (I) | $${5 \over 3}M{R^2}$$ |
| (B) | Moment of inertia of hollow sphere of radius (R) about any tangent. | (II) | $${7 \over 5}M{R^2}$$ |
| (C) | Moment of inertia of circular ring of radius (R) about its diameter. | (III) | $${1 \over 4}M{R^2}$$ |
| (D) | Moment of inertia of circular disc of radius (R) about any diameter. | (IV) | $${1 \over 2}M{R^2}$$ |
Choose the correct answer from the options given below :
A - II, B - I, C - IV, D - III
A - I, B - II, C - IV, D - III
A - II, B - I, C - III, D - IV
A - I, B - II, C - III, D - IV
Explanation
(A) Moment of inertia of solid sphere of radius R about a tangent $$ = {2 \over 5}M{R^2} + M{R^2} = {7 \over 5}M{R^2}$$
$$\Rightarrow$$ A $$-$$ (II)
(B) Moment of inertia of hollow sphere of radius R about a tangent $$ = {2 \over 3}M{R^2} + M{R^2} = {5 \over 3}M{R^2}$$
$$\Rightarrow$$ B $$-$$ (I)
(C) Moment of inertia of circular ring of radius (R) about its diameter = $${{\left( {M{R^2}} \right)} \over 2}$$
$$\Rightarrow$$ C $$-$$ (IV)
(D) Moment of inertia of circular disc of radius (R) about any diameter
$$ = {{M{R^2}/2} \over 2} = {{M{R^2}} \over 4}$$
$$\Rightarrow$$ D $$-$$ (III)
Comments (0)
