JEE MAIN - Physics (2022 - 28th June Morning Shift - No. 24)
A hanging mass M is connected to a four times bigger mass by using a string-pulley arrangement, as shown in the figure. The bigger mass is placed on a horizontal ice-slab and being pulled by 2 Mg force. In this situation, tension in the string is $${x \over 5}$$ Mg for x = ______________. Neglect mass of the string and friction of the block (bigger mass) with ice slab.
(Given g = acceleration due to gravity)
_28th_June_Morning_Shift_en_24_1.png)
Answer
6
Explanation
$$a = {{Mg} \over {4M + M}} = {g \over 5}$$ (in upward direction)
$$T = M\left( {g + {g \over 5}} \right) = {{6Mg} \over 5}$$
$$ \Rightarrow x = 6$$
Comments (0)
